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4x^2+120x-675=0
a = 4; b = 120; c = -675;
Δ = b2-4ac
Δ = 1202-4·4·(-675)
Δ = 25200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25200}=\sqrt{3600*7}=\sqrt{3600}*\sqrt{7}=60\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-60\sqrt{7}}{2*4}=\frac{-120-60\sqrt{7}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+60\sqrt{7}}{2*4}=\frac{-120+60\sqrt{7}}{8} $
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